A father has been arrested and charged with raping his own young daughter, who told police that he would demand sexual favors in exchange for outings with friends and participation in school activities.
The 46-year-old Utah resident, whose name is being withheld to protect the identity of the alleged victim, was taken into custody last week and charged Wednesday with nine counts of rape and a single count of sodomy on a child.
According to the accuser, who is now 16 years old, the abuse first started when she was only 9 years old.
Over the past seven years, the teen told police that her father, who also has two other children, raped her over 50 times.
The alleged victim explained that as she got older, her father would have sex with her more frequently. Most recently, the teen said that they would have encounters three to four times a week.
The horrific allegations came out when the 16-year-old told a friend at a church camp about the sexual abuse, asking her to keep it a secret.
The friend, however, shared the information with her parents, who then relayed it to their church bishop. The cleric, in turn, reported the allegations to officials at the Division of Child and Family Services, who notified police on June 19.
During her interview with investigators, the unnamed teen said that whenever she wanted something or wanted to go out, she would have to 'pay' her father with sexual acts.
According to a police report, earlier this month, the 46-year-old man forced his daughter to have intercourse with him four times in exchange for allowing her out-of-town best friend to visit.
When the friend left, the father told his daughter 'that it was time to pay up,' the report stated.
The paper reported that after talking to police officers about the alleged abuse committed by her father, the 16-year-old made an emotional plea no to arrest him, saying that it would 'tear her family apart' and hurt her siblings.